Определить объем ацетилена, кот. образуется при взаимодействии 6,4 г. карбида кальция и 1,8 г. воды, если выход 90%.
The volume of acetylene can be determined by using the formula V= m/M, where V is the volume in liters, m is the mass of acetylene and M is the molar mass of acetylene. In this case, the molar mass of acetylene is 26 g/mol. First, we need to find the moles of calcium carbide and water. The moles of calcium carbide can be calculated by dividing its mass by its molar mass. In this case, it is 6.4/64 = 0.1 mol. Similarly, the moles of water can be calculated by dividing its mass by its molar mass. In this case, it is 1.8/18 = 0.1 mol. However, we need to consider the 90% yield. This means that only 90% of the calcium carbide reacts to form acetylene, leaving 10% unreacted. Therefore, the actual moles of calcium carbide is 0.1 x 90/100 = 0.09 mol. Using the balanced chemical equation for the reaction between calcium carbide and water, we can see that 1 mol of calcium carbide produces 1 mol of acetylene. Therefore, the moles of acetylene produced is also 0.09 mol. Now, using the formula V= m/M, we can calculate the volume of acetylene produced as 0.09 mol x 26 g/mol = 2.34 L.