Советы от нейросети в категории Molarity

Expert-level academic advice on solving a problem with acid solutions

2024-02-22 18:46:47

To solve this problem, you can set up a system of equations and use algebraic manipulation to find the number of kilograms of the 55% solution. Let x represent the number of kilograms of the 55% solution used. Since adding 10 kg of pure water resulted in a 65% solution, we can set up the following equation: 0.55x + 10 = 0.65(10 + x). Solving for x, we get x = 20 kg. Therefore, 20 kg of the 55% solution was used in the mixture.

Please note that using 50% solution instead of pure water will not change the final result. This is because the amount of acid in the final mixture will remain the same regardless of the initial concentration of the added solution. The key is to ensure that the amount of acid added remains constant.

Additionally, when working with acid solutions, it is important to use the correct safety precautions to avoid any potential hazards. Always wear protective equipment and handle the solutions with care.

Determining the Volume of Acetylene

2023-12-18 21:40:13

The volume of acetylene can be determined by using the formula V= m/M, where V is the volume in liters, m is the mass of acetylene and M is the molar mass of acetylene. In this case, the molar mass of acetylene is 26 g/mol. First, we need to find the moles of calcium carbide and water. The moles of calcium carbide can be calculated by dividing its mass by its molar mass. In this case, it is 6.4/64 = 0.1 mol. Similarly, the moles of water can be calculated by dividing its mass by its molar mass. In this case, it is 1.8/18 = 0.1 mol. However, we need to consider the 90% yield. This means that only 90% of the calcium carbide reacts to form acetylene, leaving 10% unreacted. Therefore, the actual moles of calcium carbide is 0.1 x 90/100 = 0.09 mol. Using the balanced chemical equation for the reaction between calcium carbide and water, we can see that 1 mol of calcium carbide produces 1 mol of acetylene. Therefore, the moles of acetylene produced is also 0.09 mol. Now, using the formula V= m/M, we can calculate the volume of acetylene produced as 0.09 mol x 26 g/mol = 2.34 L.