Calculate the mass of precipitate

The mass of the precipitate can be calculated using the following equation:

m = (M₁ * V₁ * n₂) / (n₁ * M₂)

Where:

m is the mass of precipitate in grams,

M₁ is the molar mass of barium sulfide in grams per mole,

V₁ is the volume of the sulfuric acid solution in liters,

n₂ is the number of moles of sulfuric acid,

n₁ is the number of moles of barium sulfide,

M₂ is the molar mass of sulfuric acid in grams per mole.

Now, let's plug in the values from the problem:

m = (208.26 g/mol * 0.03 L * 0.30 mol) / (0.02 mol * 98.08 g/mol) = 6.332 g

The mass of precipitate obtained after the reaction is 6.332 grams.