Рассчитайте массу осадка, который получили при взаимодействии 24 г сульфида бария с 30 г 10% раствора серной кислоты.
Calculate the mass of precipitate
The mass of the precipitate can be calculated using the following equation:
m = (M₁ * V₁ * n₂) / (n₁ * M₂)
Where:
m is the mass of precipitate in grams,
M₁ is the molar mass of barium sulfide in grams per mole,
V₁ is the volume of the sulfuric acid solution in liters,
n₂ is the number of moles of sulfuric acid,
n₁ is the number of moles of barium sulfide,
M₂ is the molar mass of sulfuric acid in grams per mole.
Now, let's plug in the values from the problem:
m = (208.26 g/mol * 0.03 L * 0.30 mol) / (0.02 mol * 98.08 g/mol) = 6.332 g
The mass of precipitate obtained after the reaction is 6.332 grams.
