НОК(2, 3, 4, 5, 6, 7, 8, 9, 10)
The least common multiple (НОК) of a set of numbers is the smallest positive number that is divisible by all of the numbers in the set. To solve this problem, we first need to find the prime factorization of each number in the set. In this case, the prime factorization of 2 is 2, the prime factorization of 3 is 3, the prime factorization of 4 is 2^2, the prime factorization of 5 is 5, the prime factorization of 6 is 2 x 3, the prime factorization of 7 is 7, the prime factorization of 8 is 2^3, the prime factorization of 9 is 3^2, and the prime factorization of 10 is 2 x 5. Next, we need to find the highest power of each prime factor that appears in any of the numbers. In this case, the highest power of 2 is 3 (from 8), the highest power of 3 is 2 (from 9), the highest power of 5 is 1 (from 5 and 10), and the highest power of 7 is 1 (from 7). Now, we multiply all of these highest powers together to get the НОК(2, 3, 4, 5, 6, 7, 8, 9, 10) which is 2^3 x 3^2 x 5 x 7 = 2520.Thus, your НОК(2, 3, 4, 5, 6, 7, 8, 9, 10) is 2520.
