В ядерной модели атома водорода электрон вращается вокруг ядра (протон) по круговой орбите, радиус которой R = 5,3 • 10-11 м. Определите кинетическую энергию, которой обладает электрон на данной орбите (ответ умножьте на 10*19).
To determine the kinetic energy of the electron in the hydrogen atom, we can use the formula KE = (1/2)mv^2, where m is the mass of the electron and v is its velocity. In this case, the electron's velocity is equal to the speed of light, since it moves in a circular orbit around the nucleus. So, we can rewrite the formula as KE = (1/2)m(c^2). Now, we need to determine the mass of the electron in kilograms, which is approximately 9.11 x 10^-31 kg. Replacing this in the formula, we get KE = (1/2)(9.11 x 10^-31)(3 x 10^8)^2 = 1.636 x 10^-14 J. Multiplying this by 10^19, we get the kinetic energy of the electron on the given orbit, which is 1.636 x 10^5 keV.