The first step to solving this problem is to draw a diagram of the given situation. It would look like three masses (each with mass m) connected by identical springs, with one end attached to a wall and the other end free to move. A horizontal force F is applied to the mass on the right, causing the entire system to accelerate with an acceleration a.

Next, we need to apply Newton's Second Law of Motion: F = ma. In this case, the force F is provided by the spring connecting the rightmost mass to the wall, and the acceleration a is the same for all three masses, since they are connected by identical springs.

From the diagram, we can see that the force exerted by each spring is equal to the spring constant k multiplied by the deformation (x) of the spring. Therefore, we can write the following equation for each mass:

F = kx = ma

Since we are interested in the deformation of each spring, we can rearrange the equation to solve for x:

x = ma/k

Now, we need to find the value of the spring constant k. This can be done by using the formula for the frequency of a spring-mass system: f = 1/(2π√(k/m)). Since all three springs are identical, the frequency will be the same, and it can be calculated using the known values of the mass (m) and the frequency (f). Once we have the value of k, we can plug it into the equation x = ma/k to find the deformation of each spring.

Lastly, we need to determine the value of the applied force F. This can be done by using the formula for the work done by a spring: W = ½kx². Since we know the deformation (x) and the value of k, we can calculate the work done by each spring, and since all three springs are identical, we can simply multiply it by 3 to get the total work done by all three springs. This will be equal to the work done by the applied force F, so we can solve for F and get the final solution to the problem.