Solving the challenge of climbing the hill
We will use the following equation: M*g*h + (1/2)*M*v_0^2 = (1/2)*M*v_final^2, where M is the total mass of the body, g is the acceleration due to gravity, h is the height of the hill and v_0 and v_final are the initial and final velocities respectively.
We can rearrange the equation to solve for v_0: v_0 = √(2*g*h). Plugging in the given values, we get v_0 = √(2*10*1.5) = 7.75 m/s. Therefore, the minimum initial velocity needed to overcome the hill is 7.75 m/s.
It is worth noting that in this solution, we have assumed the body to be a point mass and have neglected friction. In a real-life scenario, these factors would have an impact on the actual minimum velocity needed.
Happy sliding!