In order to determine whether the two objects are exerting the same pressure on the table, we need to first understand what pressure is. Pressure is defined as the force per unit area. Therefore, in order for the pressure to be the same, the two objects need to have the same force and the same area of contact with the table.

Looking at the figure on the left, we can see that both objects have the same weight and are placed at the same distance from the edge of the table. This means that the two objects have the same force acting downwards. However, their contact areas with the table are different. The object on the left has a smaller contact area with the table compared to the object on the right. This means that the object on the left is exerting a larger pressure on the table compared to the one on the right.

Therefore, the objects do not exert the same pressure on the table. To evenly distribute the pressure, the objects should be placed at the same distance from the edge of the table and have the same contact area with the table. This can be achieved by placing the objects side by side instead of one on top of the other.

The first step to solving this problem is to draw a diagram of the given situation. It would look like three masses (each with mass m) connected by identical springs, with one end attached to a wall and the other end free to move. A horizontal force F is applied to the mass on the right, causing the entire system to accelerate with an acceleration a.

Next, we need to apply Newton's Second Law of Motion: F = ma. In this case, the force F is provided by the spring connecting the rightmost mass to the wall, and the acceleration a is the same for all three masses, since they are connected by identical springs.

From the diagram, we can see that the force exerted by each spring is equal to the spring constant k multiplied by the deformation (x) of the spring. Therefore, we can write the following equation for each mass:

F = kx = ma

Since we are interested in the deformation of each spring, we can rearrange the equation to solve for x:

x = ma/k

Now, we need to find the value of the spring constant k. This can be done by using the formula for the frequency of a spring-mass system: f = 1/(2π√(k/m)). Since all three springs are identical, the frequency will be the same, and it can be calculated using the known values of the mass (m) and the frequency (f). Once we have the value of k, we can plug it into the equation x = ma/k to find the deformation of each spring.

Lastly, we need to determine the value of the applied force F. This can be done by using the formula for the work done by a spring: W = ½kx². Since we know the deformation (x) and the value of k, we can calculate the work done by each spring, and since all three springs are identical, we can simply multiply it by 3 to get the total work done by all three springs. This will be equal to the work done by the applied force F, so we can solve for F and get the final solution to the problem.

Expert-level academic advice:

To solve this problem, we need to use the principles of Newton's laws of motion. According to the first law, an object at rest will remain at rest unless acted upon by an external force. In this case, the external force is the weight of the ball.

To determine the velocity of the ball when it hits the surface, we can use the equation v^2 = v0^2 + 2as, where v is the final velocity, v0 is the initial velocity, a is the acceleration, and s is the displacement.

Since the ball is free-falling, we can use the acceleration due to gravity, which is approximately 9.8 m/s^2. Also, the initial velocity is 0 m/s as the ball was dropped from rest.

Now, we need to find the displacement, which is the height of the surface from where the ball was dropped. But since the surface is horizontal, the displacement is equal to the height of the ball. Therefore, s = 0.1 m (given that the ball has a mass of 100 g).

Substituting these values in the equation, we get v = 4.43 m/s. This is the velocity of the ball when it hits the surface.

As for the impact force on the surface, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration. The mass and acceleration are the same as calculated before, so the force on the surface is F = 0.98 N.

I hope this advice helps you understand the concept of free-falling objects and their impact on different surfaces. Remember, always use the laws of physics to solve problems, not your calculator!

У нижній точці сила натягу нитки буде більша за верхню точку, і це можна пояснити наступним чином:

Сила натягу нитки залежить від ваги предмета та швидкості його обертання. У вертикальній площині, земна тя gravitation, вона наближено дорівню але меншою за силу у верхній точці.

Також, слід зазначити, що сила натягу нитки є центростремить ньій cision, і чим ближче ми до центру обертання m, тим сильніше центростремить cion iк випливає зто, якщо предмет обертається в нижній точці з меншою швидкістю, то сила натягу нитки буде більша.

Отже, сила натягу нитки в нижній точці буде більша за верхню точку, проте ми не можемо точно визначити, на скільки більша, без знання певних параметрів, таких як маса предмета та швидкість його обертання. Загалом, сила натягу нитки залежить від багатьох факторів та може бути визначена лише в конкретному випадку.

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