The solution to this problem involves finding the length of line NL. Let's look at the given information:

MN and ML are two inclined lines that form angles of 30 and 60 degrees with the plane. MN and ML intersect at point N, while points M and L are located on the plane. In other words, we have a triangle MNL where angles MNL and MLN measure 30 and 60 degrees, respectively. We are trying to find the length of line NL.

First, let's use the law of sines to find the length of line NL:

NL/sin(30) = MN/sin(60)

We know that MN is equal to a, the distance between point M and the plane. We also know that the length of extension MA of line MNL is equal to a, as it forms a right angle with the plane. Therefore, we can rewrite the law of sines as:

NL/sin(30) = a/sin(60)

Next, we can rewrite sin(60) as cos(30). This gives us:

NL/sin(30) = a/cos(30) => NL = a/sqrt(3)

Therefore, the length of line NL is equal to a divided by the square root of 3, or a over root 3. This is the final answer to the problem.

Note that the distance 'a' should be provided in the same unit of measurement as the distance 'р'; otherwise, conversion will be needed using appropriate conversion formulas.