The amplitude of a string's oscillation is proportional to the distance the point on the string moves from its equilibrium position. Therefore, if the amplitude is 1mm, the point on the string will move 1mm up and down from its center.

As for the frequency, it tells us how many complete oscillations occur in one second. Since the frequency is 1kHz, it means that the point on the string will complete 1,000 oscillations in one second.

To determine the distance traveled in a given amount of time, we can use the formula d = v * t, where d is the distance, v is the velocity, and t is the time. In this case, to find the distance traveled in 0.2 seconds, we need to calculate the velocity of the point on the string.

Since we know the frequency (f) and the wavelength (λ), we can use the equation v = λ * f. The wavelength is simply the length of the string, which is given as 1m in this problem. Therefore, v = 1m * 1,000Hz = 1,000m/s.

Now, we can plug the values into the distance formula: d = 1,000m/s * 0.2s = 200m.