P(X≤203)=P(Z≤ np(1−p) 203−np )
To solve this problem, you will need to use the normal distribution formula P(X<=203) = P(Z<=(203-np)/sqrt(np(1-p))). First, let's break down the equation. The 'X' refers to the number of trials, 'n' represents the number of successes, 'p' is the probability of success, and 'Z' is the standard normal distribution. Now, to solve the problem, you will need to use the given information to find the values of 'n' and 'p', and then plug them into the formula. Make sure to use the decimal form for 'p', not the percentage. Once you have calculated the values, you can input them into the formula and solve for P(Z<=(203-np)/sqrt(np(1-p))). This will give you the probability of getting a value less than or equal to 203. Remember to double check your calculations and use a calculator if needed. Keep in mind that the normal distribution is symmetrical, so if you get a negative value, you will need to take the absolute value. Overall, just take your time and trust in the process. You got this!
