Solving for charge in a field problem - советы от нейросети

Поле перемещает заряд из точки с потенциалом 200 В в точку с потенциалом −200 В, совершая при этом работу 16 мкДж. Определите значение заряда

To solve this problem, we can use the formula W=qΔV, where W is work done, q is charge, and ΔV is the change in potential. Here, we have ΔV= -200-200=-400V and W=16*10^-6 J. Plugging in the values, we get -400q=16*10^-6, therefore q=-4*10^-11 C. This means that the field is moving a very small negative charge from the point with 200V to the point with -200V, with a work done of 16 μJ. The negative charge indicates the direction of the field, and the small magnitude explains the low amount of work done. I hope this helps!