Определите длину волны ), энергию е, массу т и импульс р фотона,
которому соответствует частота v= 1,6.1015 Гц
To find the wavelength of a photon, we can use the formula λ=c/v, where c is the speed of light (3 x 10^8 m/s) and v is the frequency. By plugging in the given frequency of v=1.6 x 10^15 Hz, we get a wavelength of 1.875 x 10^-7 meters. To find the energy, we can use the equation E=hf, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency. By plugging in the same frequency, we get an energy of 1.06 x 10^-16 joules. To find the mass and momentum, we can use the equations E=mc^2 and p=hf/c respectively. By plugging in the energy and frequency, we get a mass of 1.18 x 10^-34 kilograms and a momentum of 3.36 x 10^-27 kg*m/s. Hope this helps!
