Сколько колебаний происходит в электромагнитной волне длиной 60 м за 5 с?
The number of oscillations in an electromagnetic wave can be determined by dividing the speed of light, which is approximately 299,792,458 meters per second, by its wavelength. In this case, we are given the wavelength to be 60 meters. So, the formula would be: number of oscillations = speed of light / wavelength. Plugging in the values, we have 299792458 / 60 = 4996540.9667 oscillations. However, this value is for one second. Since we are looking for the number of oscillations in 5 seconds, we simply multiply by 5. Thus, there will be approximately 24982704.8337 oscillations in an electromagnetic wave with a wavelength of 60 meters over a period of 5 seconds.
