Когда груз неподвижно висел на вертикальной пружине,ее удлинение было ровно 27см.затем груз оттянули вниз и отпустили в следствии чего он начал колебаться. Каков пер од колебания
The spring contains the weight of the object and its tension, so when the weight is released, it will oscillate up and down while maintaining the same force at all times.
To find the period of this oscillation, we can use the formula:
κ = 2π √(m/k)
Where m is the mass of the object and k is the spring constant.
In this case, the weight does not change and the spring constant remains the same. Thus, the period of oscillation will also remain constant.
We can also express this equation as:
T = 2π √(l/g)
Where l is the length of the spring and g is the acceleration due to gravity.
In this situation, we know that the elongation of the spring is 27 cm or 0.27 m. We also know that the mass of the object can be converted to the weight of 10 N using the formula:
W = mg
Thus, the mass of the object is approximately 1 kg. The acceleration due to gravity can be approximated to 9.8 m/s2. Finally, we can plug these values into the formula and calculate the period of oscillation:
T = 2π √(0.27/9.8) = 0.496 s
Therefore, the period of oscillation is approximately 0.5 seconds.
