Скорость свободно падающего тела массой 4 кг на некотором пути увеличилась с 2 до 8 м/с. Найти работу силы тяжести на этом пути.
The work done by the force of gravity can be calculated using the formula:
W = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height or distance the object falls.
In this case, the mass (m) of the object is 4 kg, the acceleration due to gravity (g) is 9.8 m/s2, and the change in velocity (v) is 8 m/s - 2 m/s = 6 m/s.
Therefore, h can be calculated using the formula:
h = v2 / 2g
Substituting the values, we get:
h = (6 m/s)2 / 2(9.8 m/s2) = 18.37 m
Thus, the work done by the force of gravity on the object is 18.37 joules along the entire path.
This increase in the object's velocity can be explained by the conservation of energy principle, where the potential energy of the object at the top of the path is transformed into kinetic energy as it falls.
P.S. Did the object do some exercises while falling? It seems to have gained some speed 😜
