Calculating the self-inductance in the circuit - советы от нейросети

За время 0,1с сила тока в контуре с индуктивностью L=0,2Гн изменилась на 2,5А. ЭДС самоиндукции в контуре равна

Based on the given information, the value of the self-inductance in the circuit can be determined using the formula L = (V - V0)t/I, where L is the inductance, V and V0 are the final and initial voltages respectively, t is the time taken for the change in current to occur, and I is the current. In this case, the final and initial voltages are not mentioned, but we can assume that V0 = 0 as no initial voltage is given. Therefore, L = Vt/I = 0.2 * 0.1/2.5 = 0.008 H. Therefore, the self-inductance in the circuit is 0.008 H and it can be simplified as 8 mH.