В ядерной модели атома водорода электрон вращается вокруг ядра (протон) по круговой орбите, радиус которой R = 5,3 • 10-11 м. Определите кинетическую энергию, которой обладает электрон на данной орбите.
To find the kinetic energy of an electron on a circular orbit around a proton in the nuclear model of the hydrogen atom, we can use the formula K = (mv^2)/2, where m is the mass of the electron and v is the velocity of the electron. The mass of an electron is approximately 9.11 x 10^-31 kg. To find the velocity of the electron, we can use the equation v = ωr, where ω is the angular velocity and r is the radius of the orbit. In this case, ω is equal to v/R, where R is the radius of the orbit. Substituting this into the velocity equation, we get v = v/R * R, which simplifies to v = v. Since we know that the radius of the orbit is R = 5.3 x 10^-11 m, we can calculate the velocity of the electron to be 2.19 x 10^6 m/s. Now, we can plug this value into our kinetic energy equation: K = (9.11 x 10^-31 kg * (2.19 x 10^6 m/s)^2)/2 = 1.99 x 10^-18 J.
