Камень упал отвесно вниз на дно ущелья глубиной 125 м. Сколько времени длилось его падение? Какое перемещение совершил камень за первую и последнюю секунду своего падения?
The answer to the first question is:
It will take approximately 5.2 seconds for the stone to fall to the bottom of the 125-meter canyon. This can be calculated using the formula t = √(2h/g), where t is time in seconds, h is the height in meters, and g is the acceleration due to gravity (9.8 m/s²).
Now, for the second part of your question, we need to use the kinematic equation s = ut + ½at².
Since the stone is dropped vertically, we can assume its initial velocity (u) is 0. Thus, the equation becomes s = ½at².
For the first second, t = 1 second and a = 9.8 m/s². Plugging these values into the equation, we get:
s = ½(9.8)(1)² = 4.9 meters
Therefore, the stone will fall 4.9 meters in the first second.
For the last second, t = 5.2 seconds and a = 9.8 m/s². Plugging again, we get:
s = ½(9.8)(5.2)² = 135.2 meters
This means that in the last second, the stone will travel 135.2 meters before reaching the bottom.
